K2 4498 PA

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K2 4498 PA

F5UL
Hi all the list

Thank's a lot to Gary, Jim, Toby, Luc, Don ... for your replies !

Up to now, I did statics tests resistances to ground and voltage, with power to minimum.
So, here are the results :

12V = 11.37 (I'm using a very small PS (12 v/0.5 A) to minimise the curent problem)
Input curent rx = 0.221 A
Input curent tx = start at 0.470 A and go up to more than 1 A when the supply fold down to zero!

8A = 7.98 V rx, 7.98 tx
8R = 410 ohms to ground, 7.89 rx, 0.250 tx
8T = 300 ohms to ground, 0.002 rx, 7.89 tx

Q5c = 650 ohms, 11.33 rx, 11.17 going down to zeo in tx
Q5b = 110 ohms,   0  rx, 1.23 tx
Q5e = 23 ohms,    0 rx, 0.29 tx

Q6c = 660 ohms, 11.33 rx, 11.15 going down in tx
Q6b = 65 ohms,     0 rx, 1.09 tx
Q6e = 1.5 ohms,    0 rx, 0.38 tx

Q7c = 680 ohmd, 11.32 rx, 11.27 going down in tx
Q7b = 55 ohms,   0.005 rx,  0.643 tx
Q7e = 0 ohm,  0 rx, 0 tx

Q8c = 680 ohms, 11.32 rx, 11.27 going down in tx
Q8b = 55 ohms, 0.005 rx, 0.643 tx
Q8e = 0 ohm,  0 rx, 0 tx

I stoped the test whenever the 12V reached 9.0 v in tx !!!

Well, Gary told me that I had to watch 8R going down in tx at least 0 .3 volts. The 250 mV was not far from this limit so I pushed the point and changed the 2N3906. The only result where 7.91 in rx and 0.248 in tx so...??? I do not think this switch circuit is involved!

Nothing else for now. I will try the signal tracing this afternoon and we will see what come out !

Once more thank you for your intervention and I will keep u informed of the results...

F5UL/Bob
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