Thanks pal... guess I got a bit ahead of myself there!
>Hi Tom,
>Just a small correction to your 2W to 800W example:
> From 2W to 4W (first doubling of power) = +3dB
> From 4W to 8W (2nd doubling of power) = +3dB
> From 8W to 80W (increase of 10X) = +10dB
> From 80W to 800W (increase of 10X) = +10dB
>Total = 3+3+10+10 = 26db
>
>Best 73,
>Frank - W6NEK
>
>----- Original Message ----- From: "Tom Hammond" <
[hidden email]>
>To: <
[hidden email]>; <
[hidden email]>
>Sent: Wednesday, March 30, 2005 11:01 AM
>Subject: Re: [Elecraft] OT: math question
>
>
>>At 12:01 PM 3/30/05, you wrote:
>>>How would one calculate the amplifier gain (in dB) required to go from one
>>>power level to another? For example from 5W to 100W.
>>
>>10 log(P2/P1) = 10 log(100/5) = 10 log(20) = 10 (1.30103) = 13.0103dB
>>
>>An easy 'rule of thumb' way to get a good idea of such levels
>>is to remember that:
>>
>> a power INcrease of 2 = approx. +3dB change
>> a power DEcrease of 2 = approx. -3dB change
>>
>> a power INcrease of 10 = +10dB
>> a power DEcrease of 10 = -10dB
>>
>>So, to go from 5W to 10W output, you have 3dB GAIN
>> to go from 10W to 100W, you have 10dB gain
>>
>>Since dB's can be added, going from 5W to 100W = 3db + 10 dB = 13dB
>>
>>Similarly, if you went from 2W to 800W...
>>
>> From 2W to 4W (first doubling of power) = +3dB
>> From 4W to 8W (2nd doubling of power) = +3dB
>> From 8W to 800W (increase of 10X) = +10dB
>> -------
>> Total power increase in dB = +16dB
>>
>>73,
>>
>>Tom Hammond N0SS
>>
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