Im with Adi on this one..i.e NO MATH!. Although I'm 100% certain Don is correct, my "fingers" came with *about* a 12.6 dB increase. (I never did understand those loggers)
> dBm's
>
> Just remember this (no maths:))) :
> Every 3dB increase is power multiplied by 2 times (1W to 2W is 30dBm to
> 33dBm)
> So 1W+3dB (1x2=2) is 2W+3dB (2x2=4)4W+3dB(4x2=8)8W and so on.
> Every 10dB increase is power multiplied by 10 (1W to 10W is 30dBm to 40dBm
> 100W to 1KW is 50 dBm to 60 dBm the easy one HI)
> And dont care abt digits on calcullator (try to see 0,5dB on Your S-meter or
> ask someone on the band to change the power from 100W to 50W or from 10W to
> 5W (3dB) You will see practically no difference.
> Why dBm? Because dBm is power related to 1mW=0dBm .
>
> S55M-Adi
>
>
> ----- Original Message -----
> From: "W3FPR - Don Wilhelm" <
[hidden email]>
> To: <
[hidden email]>; <
[hidden email]>
> Sent: Wednesday, March 30, 2005 8:23 PM
> Subject: RE: [Elecraft] OT: math question
>
>
> > dB = 10 log (P2/P1)
> > For your example of 5 watts to 100 watts, is an increase of 13.01029996
> dB -
> > pardon the rounding but that is all the digits my calculator shows :>).
> >
> > 73,
> > Don W3FPR
> >
> > > -----Original Message-----
> > >
> > > How would one calculate the amplifier gain (in dB) required to go
> > > from one
> > > power level to another? For example from 5W to 100W.
> > >
> > > K3UJ
> >
> >
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