Posted by
hf4me on
Dec 19, 2010; 4:11am
URL: http://elecraft.85.s1.nabble.com/kpa-500-tp5844035p5849424.html
"Squeezing higher power out degrades the IMD."
SO... The "10 watt" amp feeds the 100 w PA? Does it get fed with 10 watts
or 12 watts? What does that mean to the IMD of the 100 w PA by the cause of
the degraded IMD being fed into the PA?
73, de Jim KG0KP
----- Original Message -----
From: "Ron D'Eau Claire" <
[hidden email]>
To: <
[hidden email]>
Sent: Thursday, December 16, 2010 6:42 PM
Subject: Re: [Elecraft] kpa 500
> And if you care about transmitting the cleanest signal, you'll hold the
> K3/10 output to 10 watts PEP. Squeezing higher power out degrades the IMD.
> The Power control provides some additional room to be sure everyone can
> make
> the rated 10 watts.
>
> The same is true for the K2/10.
>
> Ron AC7AC
>
> -----Original Message-----
> Well, let's see if I can do this right: 15 db = 10 log (Pout / 12 watts)
>
> where 15db is the FCC maximum allowed gain. Assuming that 12 watts
> will drive the KPA500, we solve for Pout as: 12 watts * 10^1.5 = 379
> watts
>
> So, if I did the calculation correctly, that would be legal maximum. I
> would suspect the gain to be less, perhaps in the 200-300 watt range
> for no other reason than it feels right to my mind. There may also
> have been an email from Lyle that mentioned something in the 200 watt
> range, but I'm not sure.
>
> 73, Byron N6NUL
>
>
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