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Re: Connectors

Posted by Hisashi T Fujinaka on Apr 26, 2012; 4:16pm
URL: http://elecraft.85.s1.nabble.com/New-KAT500-pics-from-the-Visalia-DX-convention-tp7500313p7503419.html

Just a quick question:

> On 4/25/12 7:09 PM, Alan Bloom wrote:
> Since two N or UHF adapters were used, I assume the loss per connector
> is half the total. The vertical scale was .1 dB/division, so I estimated
> the insertion loss to the nearest .01 dB or so:
>
>              --------- Type N --------   ---------- UHF ----------
> FREQ (MHz)  TOTAL  LOSS PER CONNECTOR   TOTAL  LOSS PER CONNECTOR
> 1.8         0 dB   0 dB                 0 dB   0 dB
> 30          0      0                    0      0

What are the measurements below this? I'm not sure I can work any
DX at those frequencies. I always tell my microwave experimenter buddies
that if I can walk there and talk to the guy, I'll do that and not worry
about my radio. :)

> 100         0      0                    0      0
> 150         0      0                    0.02   0.01
> 200         0      0                    0.03   0.015
> 450         0      0                    0.18   0.09
> 600         0      0                    0.26   0.13
> 900         0      0                    0.66   0.33
> 1000        0.05   0.025                0.8    0.4
> 1300        0.1    0.05                 0.86   0.43
> 1600        0.05   0.025                0.5    0.25
> 2000        0.05   0.025                0.02   0.01

Oh, and for technical content: even though you get an impedance
mismatch, at the frequencies I care about the mismatch is so short that
you don't make it far around the Smith chart (easier than doing the
calculations). It doesn't really matter that a UHF connector isn't
exactly 50 ohms when it's << a wavelength, 1/10 the wavelength.

So if a UHF connector is about an inch, 10 times that is about 10
inches, or about what I think is a nanosecond is (about a foot) which is
10^9Hz or about a gigahertz.

So back-of-the-envelope, UHF connectors impedance mismatch only matters
around a gigahertz. This would horrify my engineering profs because
MIT back-of-the-envelope calculations would require Maxwell's equations.

--
Hisashi T Fujinaka - [hidden email]
BSEE(6/86) + BSChem(3/95) + BAEnglish(8/95) + MSCS(8/03) + $2.50 = latte
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