How much power cable twist is needed to be effective for reducing RFI/EMI?
John KK9A Jim Brown K9YC wrote: I find #10 to be the largest cable that I can reasonably fit into the 45A insert, so I run twisted pairs of that. 73, Jim K9YC ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[hidden email] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [hidden email] |
Buck,
Running a heavy power supply line with a lighter gauge wire at the radio end OR a lighter wire at the power supply end, the overall net supply resistance (and voltage drop) will be the same. For example, 100 Ohms in series with 1 Ohm equals 101 Ohms net total resistance. Likewise 1 Ohm in series with 100 Ohms is still 101 Ohms. It doesn't matter if you take the voltage drop at the input or at the output end of the power run if the total load is at the end of the run. I checked with Dr. Ohm to verify this. :-) Jim - W4RKS ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[hidden email] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [hidden email] |
In reply to this post by john@kk9a.com
On 4/12/2018 4:04 AM, [hidden email] wrote:
> How much power cable twist is needed to be effective for reducing RFI/EMI? More is better. :) I put black and white #10 in a vise on one end and a drill motor on the other and twist it a lot, then let it sit overnight so that it will at least partially learn its new position. :) I'd have to look, but I'd guess I'm getting 3-5 turns per foot, and it will vary from one end to the other. Note that twisting power conductors only helps prevent coupling to and from those conductors. 73, Jim K9YC ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[hidden email] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [hidden email] |
In reply to this post by Jim Wilson
> Running a heavy power supply line with a lighter gauge wire at > the radio end OR a lighter wire at the power supply end, the > overall net supply resistance (and voltage drop) will be the same. > For example, 100 Ohms in series with 1 Ohm equals 101 Ohms net total > resistance. Use *realistic* resistance values. For example, a 10 foot piece of of #8 wire (0.63 milli-Ohms per foot) with a six inch "pigtail" of #12 wire (1.5 milli-Ohms per foot) is equivalent to 11' 3" of #8 wire or less than one foot of #12 wire. The *contact resistance* in a 15A Power Pole (0.88 milli-Ohms) is, *by itself,* is equivalent to more than six inches of #12 wire. Ohm's Law is *exactly* why we would all be better off if the power jack on the K3/K3S was doubled up and the power cable replaced with #6 or #8 wire even if it were necessary to splice in some 4" pieces of #10 or #12 wire to mate with the 15A Power Pole connectors. #10 or 1/4" bolts for the power terminal with #8 wire and ring terminals on both ends would reduce the voltage drop in the power cable by 75%, if the bolted connections were torqued properly, compared to #12 wire and 15A Power Pole connectors. 73, ... Joe, W4TV On 2018-04-12 11:19 AM, James Wilson wrote: > Buck, > > Running a heavy power supply line with a lighter gauge wire at > the radio end OR a lighter wire at the power supply end, the > overall net supply resistance (and voltage drop) will be the same. > For example, 100 Ohms in series with 1 Ohm equals 101 Ohms net total > resistance. > > Likewise 1 Ohm in series with 100 Ohms is still 101 Ohms. > > It doesn't matter if you take the voltage drop at the input or > at the output end of the power run if the total load is at the > end of the run. > > I checked with Dr. Ohm to verify this. :-) > > Jim - W4RKS > ______________________________________________________________ > Elecraft mailing list > Home: http://mailman.qth.net/mailman/listinfo/elecraft > Help: http://mailman.qth.net/mmfaq.htm > Post: mailto:[hidden email] > > This list hosted by: http://www.qsl.net > Please help support this email list: http://www.qsl.net/donate.html > Message delivered to [hidden email] > Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[hidden email] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [hidden email] |
In reply to this post by Jim Brown-10
On 4/12/2018 10:07 AM, Walter Underwood wrote:
> Cat 5 cable has a different twist on each set of pairs. Those range from 52 to 72 turns per meter or 1.94 to 1.38 cm per turn. That works out to 15 to 22 turns per foot. Yes. This is done to minimize inductively coupled crosstalk between pairs, which is critical to Ethernet transmission. A pair from CAT5/6 cable used to carry audio or RF provides very good rejection of differential mode coupling to/from the cable. It's a great choice for telephone wiring if RFI to the phone line (including DSL) is a problem. A CAT5/6 pair is also a great choice for adding a ferrite common mode choke to a low band receive antenna. I've completed a set of measurements on this and will publish an applications note in the near future. 73, Jim K9YC ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[hidden email] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [hidden email] |
In reply to this post by john@kk9a.com
I run all my 12v equipment (almost anyway) on a 50A Astron PS. Since
the PS is rack-mounted in a half-height cabinet the dc cable is about 12-foot long, so I used #4 welding cable that terminates on a 30A Fuse holder. That feeds two HD barrier strip terminal blocks (for pos and neg rails). The terminals accommodate No. 10 awg cables to the heaviest current loads. A secondary strip handles small stuff (under 5A total). The PS runs 13.71v and drops to 13.5v at the fuse holder. K3 sees about 13.35v (radio is 10w version). I have only two PowerPole equipped pieces; the rest use terminals or other connectors like Molex, etc. (even one Cinch-Jones). I count 14 loads connected to the 13v power distribution (not all are used simultaneously). In the case of running to a regular-sized PP connector I just add a few inches of no.14 awg (splice is two wires soldered and covered with heat shrink) 73, Ed - KL7UW http://www.kl7uw.com Dubus-NA Business mail: [hidden email] ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[hidden email] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [hidden email] |
In reply to this post by Jim Wilson
You need to deploy the Ohm Eater to get rid of those pesky, excess Ohms....
BUT, be careful....their "droppings" can be toxic to the ruby throated Ampere. The hairy clawed Volt is however, immune. Charlie k3ICH -----Original Message----- From: [hidden email] <[hidden email]> On Behalf Of James Wilson Sent: Thursday, April 12, 2018 11:19 AM To: [hidden email] Subject: Re: [Elecraft] Astron VS-35M Powwer Supply V- Buck, Running a heavy power supply line with a lighter gauge wire at the radio end OR a lighter wire at the power supply end, the overall net supply resistance (and voltage drop) will be the same. For example, 100 Ohms in series with 1 Ohm equals 101 Ohms net total resistance. Likewise 1 Ohm in series with 100 Ohms is still 101 Ohms. It doesn't matter if you take the voltage drop at the input or at the output end of the power run if the total load is at the end of the run. I checked with Dr. Ohm to verify this. :-) Jim - W4RKS ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[hidden email] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [hidden email] |
In reply to this post by Joe Subich, W4TV-4
I believe his point was that a fat and skinny cable in series provides
the same net resistance regardless of the ordering of the pieces. Not that a real world cable would be 100 ohms. 73 Josh W6XU On 4/12/2018 9:55 AM, Joe Subich, W4TV wrote: > > > Running a heavy power supply line with a lighter gauge wire at > > the radio end OR a lighter wire at the power supply end, the > > overall net supply resistance (and voltage drop) will be the same. > > For example, 100 Ohms in series with 1 Ohm equals 101 Ohms net total > > resistance. > > Use *realistic* resistance values. For example, a 10 foot piece of > of #8 wire (0.63 milli-Ohms per foot) with a six inch "pigtail" of > #12 wire (1.5 milli-Ohms per foot) is equivalent to 11' 3" of #8 > wire or less than one foot of #12 wire. > ______________________________________________________________ Elecraft mailing list Home: http://mailman.qth.net/mailman/listinfo/elecraft Help: http://mailman.qth.net/mmfaq.htm Post: mailto:[hidden email] This list hosted by: http://www.qsl.net Please help support this email list: http://www.qsl.net/donate.html Message delivered to [hidden email] |
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