KPA-1500 Efficiency As A Function of Input Power

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KPA-1500 Efficiency As A Function of Input Power

charles-2
Thanks for the replies.

Upon further testing, I have found that the efficiency of the KPA-1500
is varies greatly with driving power.  The following table illustrates
the relationships between exciter power, voltage, current,
power-in(voltage x amps), power-out, efficiency, and dissipated power.
The following test was made with the KPA-1500 into a dummy load and
readings from the KPA-1500 utility software.

(Exciter)(Amps) (Voltage) (Power-In) (Power-Out) (Efficiency Pout/Pin)
(Dissipated Pwr)
   10w     29a     52.7v     1528w       375W        375/1528 = 24.5%    
1205w
   15w     37a     52.7v     1950w       620w        620/1950 = 31.7%    
1335w
   20w     43a     52.6v     2262w       861w        861/2262 = 38.0%    
1413w
   25w     47a     52.6v     2472w      1060w       1060/2472 = 42.8%    
1451w
   30w     51a     52.6v     2682w      1227w       1227/2682 = 45.7%    
1420w
   35w     53a     52.5v     2782w      1380w       1380/2782 = 49.5%    
1412w
   40w     55a     52.5v     2887w      1497w       1497/2887 = 51.9%    
1382w
   45w     56a     52.5v     2940w      1600w       1600/2940 = 54.4%    
1313w
   50w     57a     52.5v     2992w      1703w       1703/2992 = 56.9%    
1315w
   53w     59a     52.5v     3097w      1825w       1825/3097 = 58.9%    
1306w

The remarkable thing is that DISSIPATED POWER appears to be relatively
constant from 375w output through 1825w output.  This implies the
KPA-1500 will need to dissipate nearly the same amount of heat at low
power output as at high power output, if I am interpreting the data
correctly. I would like to know from Elecraft if this is normal
behavior.

Charles  K5UA
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Re: KPA-1500 Efficiency As A Function of Input Power

Nr4c
There was a similar post about the KPA500 in the last year or so. Elecraft responded that the amp was designed for 500 Watts running less was less efficient and running amp at low power was doing it no favors.

With the KPA500, so many wanted 1500 W so now you have it, you want to run less?

Sent from my iPhone
...nr4c. bill


> On Aug 17, 2018, at 1:17 AM, [hidden email] wrote:
>
> Thanks for the replies.
>
> Upon further testing, I have found that the efficiency of the KPA-1500 is varies greatly with driving power.  The following table illustrates the relationships between exciter power, voltage, current, power-in(voltage x amps), power-out, efficiency, and dissipated power. The following test was made with the KPA-1500 into a dummy load and readings from the KPA-1500 utility software.
>
> (Exciter)(Amps) (Voltage) (Power-In) (Power-Out) (Efficiency Pout/Pin) (Dissipated Pwr)
>  10w     29a     52.7v     1528w       375W        375/1528 = 24.5%     1205w
>  15w     37a     52.7v     1950w       620w        620/1950 = 31.7%     1335w
>  20w     43a     52.6v     2262w       861w        861/2262 = 38.0%     1413w
>  25w     47a     52.6v     2472w      1060w       1060/2472 = 42.8%     1451w
>  30w     51a     52.6v     2682w      1227w       1227/2682 = 45.7%     1420w
>  35w     53a     52.5v     2782w      1380w       1380/2782 = 49.5%     1412w
>  40w     55a     52.5v     2887w      1497w       1497/2887 = 51.9%     1382w
>  45w     56a     52.5v     2940w      1600w       1600/2940 = 54.4%     1313w
>  50w     57a     52.5v     2992w      1703w       1703/2992 = 56.9%     1315w
>  53w     59a     52.5v     3097w      1825w       1825/3097 = 58.9%     1306w
>
> The remarkable thing is that DISSIPATED POWER appears to be relatively constant from 375w output through 1825w output.  This implies the KPA-1500 will need to dissipate nearly the same amount of heat at low power output as at high power output, if I am interpreting the data correctly. I would like to know from Elecraft if this is normal behavior.
>
> Charles  K5UA
> ______________________________________________________________
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Re: KPA-1500 Efficiency As A Function of Input Power

Roy Koeppe


" Upon further testing, I have found that the efficiency of the KPA-1500 is
varies greatly with driving power."

That's the reason SPE amps have a power range selection choice setting. (Me
thinks)

73,   Roy    K6XK


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Re: KPA-1500 Efficiency As A Function of Input Power

Charlie T, K3ICH
In reply to this post by charles-2
It's normal.

Even at zero output, (keyed ON but with no drive power) the idling current
required to obtain linear class amplification will cause significant power
dissipation in the final, regardless if its solid or hollow state.

73, Charlie k3ICH




-----Original Message-----
From: [hidden email] <[hidden email]> On
Behalf Of [hidden email]
Sent: Friday, August 17, 2018 1:18 AM
To: [hidden email]
Subject: [Elecraft] KPA-1500 Efficiency As A Function of Input Power

Thanks for the replies.

Upon further testing, I have found that the efficiency of the KPA-1500 is
varies greatly with driving power.  The following table illustrates the
relationships between exciter power, voltage, current, power-in(voltage x
amps), power-out, efficiency, and dissipated power.
The following test was made with the KPA-1500 into a dummy load and readings
from the KPA-1500 utility software.

(Exciter)(Amps) (Voltage) (Power-In) (Power-Out) (Efficiency Pout/Pin)
(Dissipated Pwr)
   10w     29a     52.7v     1528w       375W        375/1528 = 24.5%    
1205w
   15w     37a     52.7v     1950w       620w        620/1950 = 31.7%    
1335w
   20w     43a     52.6v     2262w       861w        861/2262 = 38.0%    
1413w
   25w     47a     52.6v     2472w      1060w       1060/2472 = 42.8%    
1451w
   30w     51a     52.6v     2682w      1227w       1227/2682 = 45.7%    
1420w
   35w     53a     52.5v     2782w      1380w       1380/2782 = 49.5%    
1412w
   40w     55a     52.5v     2887w      1497w       1497/2887 = 51.9%    
1382w
   45w     56a     52.5v     2940w      1600w       1600/2940 = 54.4%    
1313w
   50w     57a     52.5v     2992w      1703w       1703/2992 = 56.9%    
1315w
   53w     59a     52.5v     3097w      1825w       1825/3097 = 58.9%    
1306w

The remarkable thing is that DISSIPATED POWER appears to be relatively
constant from 375w output through 1825w output.  This implies the
KPA-1500 will need to dissipate nearly the same amount of heat at low power
output as at high power output, if I am interpreting the data correctly. I
would like to know from Elecraft if this is normal behavior.

Charles  K5UA
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Re: KPA-1500 Efficiency As A Function of Input Power

K8ZCT
In reply to this post by charles-2
I believe most every electrical device and piece of equipment will have some
type efficiency curve for power in and power out.
A motor sitting at idle is using power, but doing almost no real work.
However, at no load it is still using watts. Typically a motor has the best
efficiency at around 75% load or so.

I am sure an amplifier or any electronic device is similar to a motor or
transformer. There are always "no load losses", that you need to have
regardless of the load on the device or output of the device.

Also, I am not sure you are looking at the entire picture with your numbers.
I see that you are multiplying
the DC amperes x DC volts. In reality, the power supply has to make that DC
power, and it also has some electrical power loss. You should really use a
power meter on the 240V feed from your panel to get the exact input power
required for the KPA-1500. That is why Elecraft recommends a 20A feeder at
nominal 240V input. The range of the power supply is 195V to 250V. At
maximum power output of the amp there will be less amperes used at 250V than
195V but it will require the same input power. There is a maximum power
dissipation hard fault @ 2050 watts. So, that would say if you are
dissipating 2050 watts, and putting out 1500 watts RF, that would require
3550 watts of input power. At 240V that is about 15 amps and at 195V that is
over 18 amps. You don't want to run it that high or at that efficiency. You
need to make some changes in your setup to keep below that level.

 The calculations are even worse for the "efficiency" using the power used
on the 240V side, but that is what you are really paying for in your monthly
electric bill. What you did probably is close enough for discussion and
Elecraft metering reflects those numbers, but it is worth noting there are
many factors that enter into an "efficiency" calculation. Loading the amp
into a dummy load gives you one set of data.


However, the better your antenna matches at each frequency without needing
the tuner, the less heat the tuner will create doing it's job to match to 50
ohms, so the amp can put out maximum power. Of course, if your antenna has a
high SWR, because of it's electrical design, you are just making heat
somewhere, and not putting your power used to good RF output production for
getting your station heard on the airwaves.


Bill, K8ZCT



--
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Re: KPA-1500 Efficiency As A Function of Input Power

David Gilbert
In reply to this post by charles-2


Not sure why that's a surprise.  It's a linear amp ... the bias point is
what draws the current, and therefore essentially determines the
dissipation.  There's nothing remarkable about it.

Amplifier 101.

Dave  AB7E


On 8/16/2018 10:17 PM, [hidden email] wrote:

> Thanks for the replies.
>
> Upon further testing, I have found that the efficiency of the KPA-1500
> is varies greatly with driving power.  The following table illustrates
> the relationships between exciter power, voltage, current,
> power-in(voltage x amps), power-out, efficiency, and dissipated power.
> The following test was made with the KPA-1500 into a dummy load and
> readings from the KPA-1500 utility software.
>
> (Exciter)(Amps) (Voltage) (Power-In) (Power-Out) (Efficiency Pout/Pin)
> (Dissipated Pwr)
>   10w     29a     52.7v     1528w       375W        375/1528 =
> 24.5%     1205w
>   15w     37a     52.7v     1950w       620w        620/1950 =
> 31.7%     1335w
>   20w     43a     52.6v     2262w       861w        861/2262 =
> 38.0%     1413w
>   25w     47a     52.6v     2472w      1060w       1060/2472 =
> 42.8%     1451w
>   30w     51a     52.6v     2682w      1227w       1227/2682 =
> 45.7%     1420w
>   35w     53a     52.5v     2782w      1380w       1380/2782 =
> 49.5%     1412w
>   40w     55a     52.5v     2887w      1497w       1497/2887 =
> 51.9%     1382w
>   45w     56a     52.5v     2940w      1600w       1600/2940 =
> 54.4%     1313w
>   50w     57a     52.5v     2992w      1703w       1703/2992 =
> 56.9%     1315w
>   53w     59a     52.5v     3097w      1825w       1825/3097 =
> 58.9%     1306w
>
> The remarkable thing is that DISSIPATED POWER appears to be relatively
> constant from 375w output through 1825w output.  This implies the
> KPA-1500 will need to dissipate nearly the same amount of heat at low
> power output as at high power output, if I am interpreting the data
> correctly. I would like to know from Elecraft if this is normal behavior.
>
> Charles  K5UA
> ______________________________________________________________
> Elecraft mailing list
> Home: http://mailman.qth.net/mailman/listinfo/elecraft
> Help: http://mailman.qth.net/mmfaq.htm
> Post: mailto:[hidden email]
>
> This list hosted by: http://www.qsl.net
> Please help support this email list: http://www.qsl.net/donate.html
> Message delivered to [hidden email]
>

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